Chemistry

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I think these I know how to do ....just want someone to check..still sorta mixed up on the first question. Thanx

For the following reaction, what is the correctly balanced reduction half-reaction?
Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + OH-(aq)

A. e- + Fe(OH)3(s) → Fe(s) + OH-(aq)
B. 3 e- + Fe(OH)3(s) → Fe(s) + 3 OH-(aq)
C. Fe(OH)3(s) → Fe(s) + 3 OH-(aq) + 3 e-
D. Cu(s) → Cu+(aq) + e-
I think answer is C

For the following reaction, what is the correctly balanced overall reaction?
Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + OH-(aq)

A. Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + 3 OH-(aq)
B. Fe(OH)3(s) + 2 Cu(s) → Fe(s) + 2 Cu+(aq) + OH-(aq)
C. Fe(OH)3(s) + 3 Cu(s) → Fe(s) + 3 Cu+(aq) + 3 OH-(aq)
D. 3 Fe(OH)3(s) + Cu(s) → 3 Fe(s) + Cu+(aq) + 9 OH-(aq)

i thnk answer is A

if either is wrong can sum1 explain why? thanx

  • Chemistry -

    For the following reaction, what is the correctly balanced reduction half-reaction?
    Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + OH-(aq)

    To be reduced the electrons must be added which means on the left.

    A. e- + Fe(OH)3(s) → Fe(s) + OH-(aq)
    A can't be right because OH^- doesn't balance.

    B. 3 e- + Fe(OH)3(s) → Fe(s) + 3 OH-(aq)

    C. Fe(OH)3(s) → Fe(s) + 3 OH-(aq) + 3 e-
    C can't be right because the electrons are on the right AND because the charge doesn't balance (zero on left and -6 on right).

    D. Cu(s) → Cu+(aq) + e-
    D can't be right because the electrons are on the right side
    I think answer is C

  • Chemistry -

    For the following reaction, what is the correctly balanced overall reaction?
    Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + OH-(aq)

    A. Fe(OH)3(s) + Cu(s) → Fe(s) + Cu+(aq) + 3 OH-(aq)
    A can't be right because the charge doesn't balance (zero on left and -2 on right--also the exchange of electrons is not the same).

    B. Fe(OH)3(s) + 2 Cu(s) → Fe(s) + 2 Cu+(aq) + OH-(aq)
    B can't be right because the charge doesn't balance and OH doesn't balance and electron transfer doesn't balance.

    C. Fe(OH)3(s) + 3 Cu(s) → Fe(s) + 3 Cu+(aq) + 3 OH-(aq)
    D. 3 Fe(OH)3(s) + Cu(s) → 3 Fe(s) + Cu+(aq) + 9 OH-(aq)
    D can't be right because charge doesn't balance and because electron transfer doesn't balance.

    i thnk answer is A

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