a garbage barge on the hudson river, measures 25 x 5 x 1 meters & floats in the water. how much deeper does the barge float when 4200 kg of garbage is in it?
so far, all i know is the volume of the barge is 125 m^3.
now i just don't know what to do next. please help
To determine how much deeper the barge floats when 4200 kg of garbage is added, we can use the concept of buoyancy.
First, we need to calculate the volume of the added garbage. To do this, we need to know the density of the garbage. Let's assume the density of the garbage is approximately the same as water, which is 1000 kg/m^3.
Given that the garbage has a mass of 4200 kg and assuming a density of 1000 kg/m^3, we can calculate the volume using the formula: volume = mass / density.
volume of the added garbage = 4200 kg / 1000 kg/m^3 = 4.2 m^3
Now, we need to determine the change in overall volume of the barge, considering the added garbage.
Initially, the volume of the barge is 25 m x 5 m x 1 m = 125 m^3.
After adding the garbage, the total volume becomes: 125 m^3 (barge) + 4.2 m^3 (garbage) = 129.2 m^3.
Now we find the change in depth by subtracting the initial volume from the final volume:
change in depth = final volume - initial volume = 129.2 m^3 - 125 m^3 = 4.2 m^3.
So, when 4200 kg of garbage is added to the barge, it will float approximately 4.2 meters deeper in the water.