log (32). the 2 is to the bottom of g in log
2
log (?)=3
2
Log (32)
2 = 5
Take the number at the bottom of the log and raise it to the power of the number after the "=" sign.
So 2^5 = 32.
So what do you think the answer to the next question will be?
oh thanks and then I got 8
Good job!!!
To solve the first equation, log (32) base 2, you need to find the number that, when raised to the power of 2, equals 32. In other words, you need to find the exponent that the base (2) should be raised to in order to get 32.
To solve this, you can rewrite the equation in exponential form: 2^x = 32, where x is the unknown exponent.
Now you need to find the value of x. Taking the logarithm of both sides with base 2 will help you solve for x:
log base 2 (2^x) = log base 2 (32)
The logarithm base 2 of 2 is equal to 1, so the equation simplifies to:
x = log base 2 (32)
Using a calculator, you can evaluate this logarithm to get the value of x. The result should be approximately 5.
Therefore, log (32) base 2 = 5.
To solve the second equation, log base 2 (?)=3, you need to find the number that, when raised to the power of 2, equals the base 2 logarithm of 3.
Similarly, you can rewrite the equation in exponential form: 2^x = 3, where x is the unknown exponent.
Taking the logarithm of both sides with base 2:
log base 2 (2^x) = log base 2 (3)
Again, since log base 2 (2) equals 1:
x = log base 2 (3)
Using a calculator, you can evaluate this logarithm to get the value of x. The result should be approximately 1.585.
Therefore, log base 2 (?) = 3 is approximately equal to x = 1.585.