Pre-Cal

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1)find f(g(x))

f(x) = x^2 + 2x g(x) = 1/x

x^3 + 2x

Is this correct?

2) solve: 3^x-1 = 10

ln 3/ ln 10 = .264

Is this correct? I am not sure how to do these.

3) Solve: 3^x+2 - 4 = 12

  • Pre-Cal -

    no to both answers

    1. f(x) = x^2 + 2x , g(x) = 1/x

    then
    f(g(x)
    = f(1/x)
    = (1/x)^2 + 2(1/x) = 1/x^2 + 2/x or (1+2x)/x^2

    2.
    the way you typed it, ...
    3^x - 1 = 10
    3^x = 11
    x = ln11/ln3 = 2.182658

    If you meant to type
    3^(x-1) = 10
    then
    x-1 = ln10/ln3
    x = ln10/ln3 + 1
    =3.0959

    3. Again I don't think you meant what you typed
    Was it 3^(x+2) - 4 = 12 ???
    if so then ...
    3^(x+2) = 16
    x + 2 = ln16/ln3
    x = ln16/ln3 - 2 = .5237

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