I fyou start with 2 and count by 4s until youreach the number 202, you will have the following number sequence. 2, 6, 10, 14...202

If 2 is the first number in the sequence, 6 is the second and so on, what number in the sequence is 202?

To find out which number in the sequence 2, 6, 10, 14...202 corresponds to the number 202, we need to determine the position or index of 202 in the sequence.

The sequence is formed by starting with 2 and adding 4 to the previous number repeatedly. So, we can find the index of 202 by calculating how many times we added 4 to the initial number 2 to reach 202.

We can set up an equation to find the index:

2 + (index - 1) * 4 = 202

Now, we can solve this equation to find the value of the index:

2 + 4 * (index - 1) = 202
4 * (index - 1) = 200
(index - 1) = 200 / 4
(index - 1) = 50

Adding 1 to both sides of the equation, we get:

index = 51

So, the number 202 corresponds to the 51st position in the sequence.

tn = a + (n-1)d

202 = 2 + (n-1)(4)
200 = 4n - 4
204 = 4n
n = 51

term51 is 202

Express 38605 in decimal point