chemistry

posted by .

There is 0.150 moles of H2 and I2, and are brought to equilibrium in a 3.30 L flask. The equation is H2 + I2 = 2HI. Find the equilibrium amounts of H2, I2, and HI.

I'm not getting the correct answer. I set up the formula as x^2/(.04545-x) (.04545-x). To get moles I multiplied the resulting molar concentration by the 3.30 liters. what am i doing something wrong

  • chemistry -

    and KC = 50.2

  • chemistry -

    If you are letting x stand for the amount of H2 and I2 that combine, then HI = 2x; otherwise what you have looks ok to me.

  • chemistry -

    so the equation would be 2x/(.04545-x)(.04545-x)?

  • chemistry -

    i mean 2x^2?

  • chemistry -

    I would use 2x^2. yes.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    Consider the gas-phase equilibrium A ⇌ B. In a series of experiments, different initial amounts of A and B are mixed together, and the mixture in each case is allowed to come to equilibrium. Which one of these experiments would …
  2. Chemistry

    Consider the gas-phase equilibrium A ⇌ B. In a series of experiments, different initial amounts of A and B are mixed together, and the mixture in each case is allowed to come to equilibrium. Which one of these experiments would …
  3. chemistry

    An equilibrium mixture of SO2,SO3 and O2 gases is maintained in a 11.5 L flask at a temp at which Kc=55.2 for the rxn shown below. If the number of moles of SO3 in the flask at equilibrium is twice the num of moles of SO2, how much …
  4. Chemistry

    Consider the following equilibrium at 1000K: 2SO2 (g) + O2 (g) ¡ê 2SO3 (g) A study of this system reveals that there are 3.5E-3 moles of sulfur dioxide gas, and 4.8E-3 moles of oxygen gas present in a 11.0L flask at equilibrium. …
  5. Chemistry***

    A mixture containing 19.8 moles of H2 and 7.2 mole of I2 was allowed to reach equilibrium in a 5 L closed vessel at ToC according to the equation: H2 (g) + I2 (g) 2HI (g) At equilibrium, 14 moles of H2 was present. The equilibrium …
  6. chem12

    for the equilibrium 2HI(g)--- H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 …
  7. chem 12

    for the equilibrium 2HI(g)--- H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 …
  8. chem12

    2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …
  9. chem12

    2HI(g)--H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= -2x …
  10. Chemistry!!! PLZ PLZ HELP!!

    Calculate the equilibrium amounts of each susbtance in the reaction below if an initial amount of 0.1 moles of H2 are brought together with an initial amount of 0.2 moles of I2 and then equilibrium is established at 900K. Kc at this …

More Similar Questions