chemistry
posted by anonymous .
There is 0.150 moles of H2 and I2, and are brought to equilibrium in a 3.30 L flask. The equation is H2 + I2 = 2HI. Find the equilibrium amounts of H2, I2, and HI.
I'm not getting the correct answer. I set up the formula as x^2/(.04545x) (.04545x). To get moles I multiplied the resulting molar concentration by the 3.30 liters. what am i doing something wrong

and KC = 50.2

If you are letting x stand for the amount of H2 and I2 that combine, then HI = 2x; otherwise what you have looks ok to me.

so the equation would be 2x/(.04545x)(.04545x)?

i mean 2x^2?

I would use 2x^2. yes.