# pre-calculus

posted by .

the function has a real zero in the given interval. approximate this solution correct to two decimal places: f(x)=x^4-x^3-7x^2+5x+10; (2,3)

• pre-calculus -

y =x^4-x^3-7x^2+5x+10
y' = 4x^3 -3x^2 -14x +5
calculate y there call it y1
calculate y' there, call it m
next guess at x2 = x1 - y/m

• pre-calculus -

thank you for your time and work. i really appreciate it. god bless you.

## Similar Questions

1. ### Pre-calculus

Approximate the greatest real zero of the function g(x)=x^3-3x+1 to the nearest tenth.
2. ### math

the function has a real zero in the given interval. approximate this solution correct to two decimal places. f(x)=x^4-x^3-7x^2+5x+10; (2,3)
3. ### calculus

Find the interval which contains a zero for the given function. The use Newton's method to approximate the zero of the function within 0.001. a.) f(x)=x^3+x-1 b.)f(x)=2x^3+x^2-x-+1
4. ### Calculus

An important problem in mathematics is that of root finding: that is, given a function f (x), finding any roots of f in an interval. Exact methods exist for many functions: • In the case of a linear function f (x) = ax + b, this …
5. ### pre-calculus

solve the following logarithmic equation. be sure to reject any value of x that is not in the domain of the original logarithmic expression. give the exact answer. then, use the calculator to obtain a decimal appromiation, correct …
6. ### Pre-calculus

Given f(x)=6x^4-7x^3-23x^2+14x+3, approximate each real zero as a decimal to the nearest tenth.
7. ### Calculus

The function defined below satisfies the Mean Value Theorem on the given interval. Find the value of c in the interval (1, 2) where f'(c)=(f(b) - f(a))/(b - a). f(x) = 1.5x-1 + 1.1 , [1, 2] Round your answer to two decimal places.
8. ### Calculus

The function defined below satisfies Rolle's Theorem on the given interval. Find the value of c in the interval (-3, -2) where f'(c)=0. f(x) = x + 6x-1 , [-3, -2] Round your answer to two decimal places.
9. ### Calculus

The function defined below satisfies Rolle's Theorem on the given interval. Find the value of c in the interval (0,1) where f'(c)=0. f(x) = x3 - 2x2 + x, [0, 1] Round your answer to two decimal places.
10. ### Math - Studying for Pre Calc exam!

Approximate the solutions (to three decimal places) of the given equation in the interval (- pi/2, pi/2) 6 sin 2x − 8 cos x + 9 sin x = 6 Can you help with this please?

More Similar Questions