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Precalculus(URGENT)

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Number of possible turning points in the following equation
f(x)=x^2(x-3)(x+4)
show work please

  • Precalculus(URGENT) -

    Sorry, I only do the non-URGENT ones

  • Precalculus(URGENT) -

    look at the factors. THere is a turning point at 3, -4. At zero, f(x) keeps the same curvature.

  • Precalculus(URGENT) -

    so does that mean there are 2 turning points

  • Precalculus(URGENT) -

    Number of possible turning points in the following equation
    f(x)=x^2(x-3)(x+4)
    are there 2 turning points or three turning points on the graph

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