# Precalculus(URGENT)

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Number of possible turning points in the following equation
f(x)=x^2(x-3)(x+4)

• Precalculus(URGENT) -

Sorry, I only do the non-URGENT ones

• Precalculus(URGENT) -

look at the factors. THere is a turning point at 3, -4. At zero, f(x) keeps the same curvature.

• Precalculus(URGENT) -

so does that mean there are 2 turning points

• Precalculus(URGENT) -

Number of possible turning points in the following equation
f(x)=x^2(x-3)(x+4)
are there 2 turning points or three turning points on the graph

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