Precalculus(URGENT)
posted by Arielt .
Number of possible turning points in the following equation
f(x)=x^2(x3)(x+4)
show work please

Precalculus(URGENT) 
drwls
Sorry, I only do the nonURGENT ones

Precalculus(URGENT) 
bobpursley
look at the factors. THere is a turning point at 3, 4. At zero, f(x) keeps the same curvature.

Precalculus(URGENT) 
Arielt
so does that mean there are 2 turning points

Precalculus(URGENT) 
Arielt
Number of possible turning points in the following equation
f(x)=x^2(x3)(x+4)
are there 2 turning points or three turning points on the graph
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