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What volume of 0.123 M K3PO4 is required to react with 60 mL of 0.862 M MgCl2 according to the equation

2K3PO4+3MgCl2--> Mg3(PO4)2+6KCl

Answer in units of mL.

  • chemistry -

    1. Convert MgCl2 to moles. moles = M x L.
    2. Using the coefficients in the balanced equation, convert moles MgCl2 to moles K3PO4.
    3. Remembering M = moles/L, you have moles and you have M, calculate L and convert to mL.

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    840.9756098

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