# Physics

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Find the orbital speed of an ice cube in the rings of Saturn, if the mass of Saturn is 5.67 × 1026 kg and the rings
have an average radius of 100,000 km.

• Physics -

Newton's law of gravitation:
F = G m1 m2 /r^2
let m2 = mass of ice cube and
s = G m1/r^2
so,
F = s m2
rearranging,
s = m2/F
let V = orbital speed
centripetal acceleration = V^2/r

For an object to remain in orbit s must equal the centripetal acceleration so,
s = V^2/r

• Physics -

Taking up where FredR left off,

V^2/r = G m/r^2
V^2 = G m/r
where m is the mass of Saturn.

G = 6.674*10^-11 N*m^2/kg^2

Solve for V

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