Math  Calculus
posted by Alex .
Show that the equation
log y = 1.54  .008x  .658 log x
is equivalent to
y = 34.7 (1.0186)^(x) * x^(.658)

take the antilog of each side
y= 10^(1.54.008x.658logx)
y= 10^1.54 * 10^(.008*x) * x^.658
= 34.7((10^.008)^x)*x^.658
you can take it from here.
remember log a+logb = log ab
and a^xy= (a^x)^y
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