Algebra
posted by Kelli .
log3 (2x – 1) – log3 (x – 4) = 2

log3 (2x – 1) – log3 (x – 4) = 2 , clearly x > 4
(2x1)/(x4) = 3^2
2x^2 9x5 = 0
(2x+1)(x5) = 0
x = 1/2 or x = 5
but x > 4, so
x = 5
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