ALGEBRA

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to solve the following:
4-s over 7-s = 3 over s-7...
LCD is s-7
then
(s-7)(4-s over 7-s) = (s-7) (3 over s-7)?
am I on the right track???

  • ALGEBRA -

    4-s over 7-s = 3 over s-7
    (4-s)/(7-s) = 3/(s-7)
    notice one denominator is the negative of the other, so
    (s-4)/(s-7) = 3/(s-7)
    then
    s - 4 = 3
    s = 7
    BUT;, s = 7 makes our denominators zero and our fractions would be undefined, so ...
    no solution.

  • ALGEBRA -

    i forgot about the zero thing. thank you

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