How much heat is absorbed by the calorimeter if the temperature change is 8 C and the calorimeter constant (Heat Capacity) is 3.3 J/K?
Your Answer:
See Bob Pursley's response below.
77J
To calculate the amount of heat absorbed by the calorimeter, you can use the formula:
Q = C * ΔT
Where:
Q is the amount of heat absorbed
C is the calorimeter constant (also known as heat capacity)
ΔT is the temperature change
In this case, the temperature change (ΔT) is given as 8°C and the calorimeter constant (C) is given as 3.3 J/K.
Now, substitute these values into the formula:
Q = 3.3 J/K * 8°C
Note that temperature change needs to be converted from Celsius to Kelvin, as the SI unit for temperature is Kelvin. To convert from Celsius to Kelvin, you simply add 273.15. So, in this case:
ΔT = 8°C + 273.15 = 281.15 K
Now, substitute the value of ΔT into the formula:
Q = 3.3 J/K * 281.15 K
Q ≈ 929.295 J
Therefore, the amount of heat absorbed by the calorimeter is approximately 929.295 J.