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College Chemistry II

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Determine the pH for .16M of NaC2H3O2.

Determine the pH for .18M of NaCl.

  • College Chemistry II -

    NaC2H3O2 is sodium acetate. Let's call the acetate ion Ac^-.
    Ac^- + HOH ==> HAc + OH^-

    Kb = (Kw/Ka) = (HAc)(OH^-)/(Ac^-)
    Set up an ICE chart and solve for OH^-, convert to H^+, then to pH.

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