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The magnification of a convex mirror is +0.65X for objects 2.8 m from the mirror. What is the focal length of this mirror?

  • Physics -

    Since it is convex, the focal length is negative. From the magnification,you know that the image distance is Di = -0.65 Do. The image distance Di is negative because it is a virtual image, behind the mirror.

    Now solve

    1/Do + 1/Di = 1/Do -1/0.65 Do = 1/f
    (1 - 1.538)/Do = 1/f

    -0.538/Do = 1/f

    f = -1.86 Do = -5.2 m

  • Physics -

    Thank you!

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