College Chem II

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Determine the [H3O+] of a 0.160M solution of benzoic acid.

  • College Chem II -

    Benzoic acid = HBz

    HBz ==> H^+ + Bz^-

    Ka = (H^+)(Bz^-)/(HBz)
    Set up an ICE chart, substitute into the Ka expression, and solve for (H^+), then convert to pH. You will need to look up the Ka for benzoic acid.

  • College Chem II -

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