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a chemist reacts 8.85g or iron with an excess oh hydrogen chloride to form hydrogen gas and iron(II)chloride.calculate the theoretical yield and the percentage yield of hydrogen if 0.27g H2 are collected

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    Write and balance the equation.
    2Fe + 6HCl ==> 2FeCl3 + 3H2

    Convert 8.85 g Fe to moles. moles = grams/molar mass.

    Using the coefficients in the balanced equation, convert moles Fe to moles H2.

    Now convert moles H2 to grams. grams = moles H2 x molar mass H2. This is the theoretical yield.

    The above works most simple (not limiting reagent) stoichiometry problems. Print and save this for future reference.
    %yield = (actual yield/theoretical yield)*100 = ??

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