How many grams of CuSO4 .5H2O are needed to prepare 50 ml of 0.30M CuSO4 solution
3.7452g of CuSO4.5H2O
To calculate the amount of CuSO4 .5H2O needed, we can use the formula:
Molarity (M) = moles/volume (L)
First, we need to calculate the moles of CuSO4 required:
Moles = Molarity × Volume
= 0.30 mol/L × 0.050 L
= 0.015 mol
Next, we need to convert the moles of CuSO4 into grams using its molar mass:
Molar mass of CuSO4 .5H2O = (63.55 g/mol Cu + 32.07 g/mol S + 4 × 16.00 g/mol O) + 5 × (1.01 g/mol H + 16.00 g/mol O)
= 249.68 g/mol
Grams = Moles × Molar mass
= 0.015 mol × 249.68 g/mol
= 3.7452 g (rounded to four decimal places)
Therefore, you would need approximately 3.7452 grams of CuSO4 .5H2O to prepare 50 ml of 0.30M CuSO4 solution.
To calculate the number of grams of CuSO4 · 5H2O needed to prepare a 0.30M CuSO4 solution, you need to go through the following steps:
Step 1: Determine the molar mass of CuSO4 · 5H2O.
The molar mass is the sum of the atomic masses of each element in the compound.
- Cu: 63.55 g/mol
- S: 32.06 g/mol
- O: 16.00 g/mol (x 4 for 4 oxygen atoms)
- H: 1.01 g/mol (x 10 for 10 hydrogen atoms)
Molar mass of CuSO4 · 5H2O =
(63.55 g/mol Cu) + (32.06 g/mol S) + (16.00 g/mol O × 4) + (1.01 g/mol H × 10) + (16.00 g/mol O × 5) + (1.01 g/mol H × 2)
= 249.68 g/mol
Step 2: Convert the volume of the solution to liters.
Since the molarity is given in moles per liter (M), we need to convert the milliliters (ml) to liters (L).
50 ml ÷ 1000 ml/L = 0.05 L
Step 3: Calculate the number of moles of CuSO4 needed.
Molarity (M) is defined as moles of solute per liter of solution.
Moles = Molarity × Volume (in liters)
Moles = 0.30 mol/L × 0.05 L
Moles = 0.015 moles
Step 4: Calculate the mass of CuSO4 · 5H2O needed.
Mass (in grams) = Moles × Molar mass
Mass = 0.015 moles × 249.68 g/mol
Mass = 3.744 grams
Therefore, you would need 3.744 grams of CuSO4 · 5H2O to prepare 50 ml of 0.30M CuSO4 solution.