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Suppose a solution containing 3.50 g of Na3PO4 is mixed with an excess of Ba(NO3)2. How many grams of Ba(PO4)2 can be formed.

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    No Ba(PO4)2 is formed. Ba3(PO4)2 is formed.
    This is a stoichiometry problem. All such problems are worked alike. Print this out and save it for future reference.
    1. write the equation and balance it.
    2Na3PO4 3Ba(NO3)2 ==> Ba3(PO4)2 + 6NaNO3

    2. Convert 3.50 g Na3PO4 to moles. moles = grams/molar mass

    3. Using the coefficients in the balanced equation, convert moles Na3PO4 to moles Ba3(PO4)2.

    4. Now convert moles to grams.
    g Ba3(PO4)2 = moles x molar mass.

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