posted by Kerry .
Suppose a solution containing 3.50 g of Na3PO4 is mixed with an excess of Ba(NO3)2. How many grams of Ba(PO4)2 can be formed.
No Ba(PO4)2 is formed. Ba3(PO4)2 is formed.
This is a stoichiometry problem. All such problems are worked alike. Print this out and save it for future reference.
1. write the equation and balance it.
2Na3PO4 3Ba(NO3)2 ==> Ba3(PO4)2 + 6NaNO3
2. Convert 3.50 g Na3PO4 to moles. moles = grams/molar mass
3. Using the coefficients in the balanced equation, convert moles Na3PO4 to moles Ba3(PO4)2.
4. Now convert moles to grams.
g Ba3(PO4)2 = moles x molar mass.