Nitrogen and hydrogen react to form ammonia. Consider the mixture of N2 and H2 in a closed container.
In this container there are 6 diatomic molecules of hydrogen and 6 diatomic molecules of nitrogen.
assuming the reaction goes to completion draw a representation of the product mixture. explain how you arrived at this representation.
write the balanced equation
N2+3(H2)--> 2(NH3)
Here is an answer I gave to Mary about two pages ago.
http://www.jiskha.com/display.cgi?id=1267654444
To represent the product mixture, we need to understand the stoichiometry of the reaction between nitrogen (N2) and hydrogen (H2) to form ammonia (NH3).
The balanced chemical equation for this reaction is:
N2 + 3H2 -> 2NH3
According to the stoichiometry, one molecule of nitrogen (N2) reacts with three molecules of hydrogen (H2) to produce two molecules of ammonia (NH3).
Given that there are 6 diatomic molecules of hydrogen (H2) and 6 diatomic molecules of nitrogen (N2) in the container, we can determine the amount of ammonia (NH3) that will be produced.
Since each nitrogen molecule (N2) reacts with three hydrogen molecules (H2), the number of moles of nitrogen is 6 divided by 2, which gives us 3 moles of nitrogen.
Similarly, the number of moles of hydrogen is 6 divided by 3, which gives us 2 moles of hydrogen.
According to the stoichiometry, if we have 3 moles of nitrogen, it will react with 3 x 2 = 6 moles of hydrogen.
However, since we only have 2 moles of hydrogen available, the hydrogen will be the limiting reagent. This means that all 2 moles of hydrogen will react with nitrogen, and the remaining nitrogen will be in excess.
Therefore, the reactants will be completely consumed, and the product mixture will consist of 2 moles of ammonia (NH3).
Considering the reaction goes to completion, we can draw a representation of the product mixture as follows:
2NH3
This representation indicates that all the reactants have been converted to ammonia, as dictated by the balanced chemical equation.