Nitrogen and hydrogen react to form ammonia. Consider the mixture of N2 and H2 in a closed container as illustrated below.
The container contains 6 hydrogen atoms and 6 nitrogen atoms (all diatomic)
Assuming the reaction goes to completion, draw a representation of the product mixture. Explain how you arrived at this representation.
You couldn't draw the picture in your "illustrated below" example and neither can I.
You must have something like this/
H-H ......N-N
H-H ......N-N
H-H.......N-N
That's 6 H atoms and 6 N atoms. I would draw a circle around ONE of the top N atoms, two of the top H atoms and one H of the second row showing 1 NH3 was formed. Then I would do the same kind of thing for the top N on the right, the one H on the second row and both H atoms on the third row. That represents another NH3 formed. That leaves 4 N atoms un-reacted, 2 NH3 molecules formed, and no atoms H remaining.
That makes sense when you consider the equation is N2 + 3H2 ==> 2NH3 doesn't it>
This would form two NH3 molecules, and leave 5 N2 pairs.
It would be:
NH3
N2 N2 N2 N2 N2
NH3
To represent the product mixture of the reaction between nitrogen (N2) and hydrogen (H2) to form ammonia (NH3), we need to consider the stoichiometry of the reaction. The balanced chemical equation for this reaction is:
N2 + 3H2 → 2NH3
This means that for every 1 molecule of N2, we need 3 molecules of H2 to produce 2 molecules of NH3.
In the given container, we have 6 hydrogen atoms and 6 nitrogen atoms, which means we have 6/2 = 3 molecules of H2 and 6/2 = 3 molecules of N2.
Now, using the stoichiometry of the reaction, we can determine the product mixture.
For every 1 molecule of N2, we need 3 molecules of H2. Since we have 3 molecules of N2, we will need 3 * 3 = 9 molecules of H2.
Thus, the product mixture will contain 9 molecules of H2 and 3 molecules of N2 reacting to form 2 * 3 = 6 molecules of NH3.
Therefore, the representation of the product mixture would be:
3N2 + 9H2 → 6NH3
To represent the product mixture of the reaction between nitrogen (N2) and hydrogen (H2) to form ammonia (NH3), we first need to determine the stoichiometry of the reaction.
In the balanced chemical equation for this reaction, the stoichiometric ratio between nitrogen and hydrogen is 1:3. This means that 1 molecule of N2 reacts with 3 molecules of H2 to produce 2 molecules of NH3.
Given that we have 6 hydrogen atoms and 6 nitrogen atoms, we can calculate the number of NH3 molecules formed as follows:
Number of H2 molecules = 6 hydrogen atoms / 2 hydrogen atoms per H2 molecule = 3 H2 molecules
Number of N2 molecules = 6 nitrogen atoms / 2 nitrogen atoms per N2 molecule = 3 N2 molecules
Since the stoichiometry is 1:3, we know that we need an equal number of N2 and H2 molecules for the reaction to go to completion. Here, we have 3 molecules of N2 and 3 molecules of H2, which matches the stoichiometry.
Now we can calculate the number of NH3 molecules formed:
Number of NH3 molecules = (number of N2 molecules) * 2 = 3 N2 molecules * 2 NH3 molecules per N2 molecule = 6 NH3 molecules.
Therefore, the representation of the product mixture can be drawn as 6 molecules of NH3.
NH3 NH3 NH3 NH3 NH3 NH3
I arrived at this representation by first determining the stoichiometry of the reaction using the balanced chemical equation. Then, based on the given number of hydrogen and nitrogen atoms, I calculated the corresponding number of N2 and H2 molecules. Finally, using the stoichiometric ratio, I determined the number of NH3 molecules formed and represented this in the product mixture.