math
posted by Crystal .
32x^2y64xy4x^3y. When I factored out the GCF, I got 4. When I try to factor is completely, I got lost and confused. Can someone please help???

Your GCF is 4xy
32x^2y64xy4x^3y
= 4xy(8x  16  x^2)
(expand the answer to verify)
Respond to this Question
Similar Questions

hard math
please someone help me! i've tried so hard! factor m^6 + n^2 28x^2y^2  7x^4 8x^3y^3 +343z^3 thank you so much!!! For the second one: 28x^2y^2  7x^4 Factor out 7x^2: 7x^2(4y^2  x^2) Now we try to factor 4y^2  x^2, which is: (2y … 
math
can anyone help with this? suppose you bought some 32 cents stamps and some 20 cents stamps. you spent $3.92 for 16 stamps. how many of each stamp did you buy? 
Math2[Please Check Again]
Problem: a^29 a^23a  *  a^2 a^2+a12 What I Got: 33a  a4 *Please Check My Work.* Nope. factor the denominator to a^2(a+4)(a3) The last factor divides out in the numerattor (second term factors to a(a3). The a … 
Math!
Factoring Completely! 13b^213 I got (13b13)(1b1). On my test my teacher said it was party wrong.And she underlined the two Thirteen's i had in my answer. And i don't understand why!? 
math
Consider the following binomials. A=(x^2+5x) B=(6x+30) Part 1: Factor each binomial by finding the GCF. Then, add the two factored binomials to make a single expression. Part 2: Now add the original forms of binomial A and B together … 
Algebra
Can someone help me with this please. Andrew factored the expression 20x^312x^2+8x as 4x(5x^212x^2+8x) but when melissa applied the distributive law and multiplied out 4x(5x^212x^2+8x)she got 20x^348x^3+32x thus Andrews solution … 
math exponents
i need to write each expression as a product of the same factor: * = multiply can you check these please a^2 i got a*a 19^3 i got 19*19*19 6^2 i got 6*6*1 x^3 i got x*x*x*1 (5)^4 i got (5)*(5)*(5)*(5)*(5) 4^3 i got 4*4*4 … 
MATH
i need to write each expression as a product of the same factor: * = multiply can you check these please a^2 i got a*a 19^3 i got 19*19*19 6^2 i got 6*6*1 x^3 i got x*x*x*1 (5)^4 i got (5)*(5)*(5)*(5)*(5) 4^3 i got 4*4*4 … 
precal
Hi I know is is probably basic but can anyone assist with the following : Find all real Roots, expressing as whole # and # under radical sign, not as fraction. and factor completely f(x)= X^32x^215x+30 I got roots at 2 (x2) and … 
Algebra 1
Simplify (2xy^3)^5 A: 32x^5y^15 B: 32/x^5y^15 C: 1/32x^5y^15 D: 1/32x^4y^2 I have a good understanding of Exponents, its just that I don't get this one. I feel like it is C but at the same time I feel like it is B. I got C though …