To reduce 32 grams of a 25% solution of antiseptic to a 10% solution, how much distilled water should a pharmacist add?
The answer is 48g. This is 2017 people!!!
boi itz 2019
.25(32) + x = .1(32+x)
solve
To solve this problem, we need to understand the concept of dilution and use some basic calculations. The formula for dilution is:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (expressed as a decimal)
V1 = initial volume of the solution
C2 = final concentration of the solution (expressed as a decimal)
V2 = final volume of the solution
In this case, we are starting with a 25% solution and want to end up with a 10% solution. Let's assign the following variables:
C1 = 0.25 (25% expressed as a decimal)
V1 = volume of the initial solution (unknown)
C2 = 0.10 (10% expressed as a decimal)
V2 = volume of the final solution (unknown)
Now, we can plug the values into the dilution formula:
C1V1 = C2V2
0.25 * V1 = 0.10 * (V1 + x)
Here, x represents the volume of distilled water to be added.
Let's now solve for x:
0.25 * V1 = 0.10 * V1 + 0.10 * x
0.25 * V1 - 0.10 * V1 = 0.10 * x
0.15 * V1 = 0.10 * x
x = (0.15 * V1) / 0.10
x = 1.5 * V1
To find the amount of distilled water (x), we need to know the initial volume of the solution (V1). If the initial volume is not given in the question, we cannot find the exact amount of water to add.