Bromine can be added to limonene to create a brominated compound.
When 613 mg of limonene and
3.5 mL of a 10% (v/v) solution of Br2 in dichloromethane (a solvent) are
combined, 959 mg of the product is isolated. Calculate the percent yield
for this reaction.
If the limonene reactant is composed of a single enantiomer, would you expect the product to be a single enantiomer or
racemic? Explain.
.... try :
.613g/136.23g/mol=.004999mol
.959g/296.04g/mol=.003239mol
Divide:
.003239/.004999 then *100% = Percent yield
=72% yield?
To calculate the percent yield, you need to compare the actual yield with the theoretical yield. The percent yield formula is:
Percent yield = (actual yield / theoretical yield) x 100
To calculate the theoretical yield, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed in the reaction, limiting the amount of product that can be formed.
In this case, we have 613 mg of limonene and 3.5 mL of 10% (v/v) solution of Br2 in dichloromethane. First, let's convert the volume of the solution into mass:
Mass of Br2 in solution = 3.5 mL x (10 g/100 mL) x (1 g/mol) = 0.35 g
Next, we need to determine the moles of limonene and Br2:
Molar mass of limonene = 136 g/mol
Moles of limonene = 613 mg / (136 g/mol) = 4.51 mmol
Molar mass of Br2 = 159.8 g/mol
Moles of Br2 = 0.35 g / (159.8 g/mol) = 2.19 mmol
The balanced equation for the reaction between limonene and Br2 is not provided, so we cannot determine the stoichiometry or the theoretical yield straightforwardly. However, we can still calculate the percent yield using the given information.
Percent yield = (actual yield / theoretical yield) x 100
In this case, the actual yield is stated as 959 mg.
To determine if the product is a single enantiomer or racemic, we need to consider the stereochemistry of the reaction. If the reaction is a stereospecific reaction, which means that only a specific enantiomer of the reactant leads to the formation of a specific enantiomer of the product, then the product will be a single enantiomer. However, if the reaction is not stereospecific, the product will likely be a racemic mixture, containing equal amounts of the two enantiomers.
Without knowing the specific reaction and conditions, we cannot definitively determine if the reaction is stereospecific or not.