how much solute is needed to prepare 450ml of a 2.0% (m/v) potassium chloride solution?
To calculate the amount of solute needed, we need to know the concentration expressed as a mass/volume percentage (m/v) and the volume of the solution being prepared.
In this case, we want to prepare a 450 mL solution with a concentration of 2.0% (m/v) potassium chloride.
Step 1: Convert the desired concentration to grams of solute per 100 mL of solution.
2.0% (m/v) means there are 2 grams of solute per 100 mL of solution.
Step 2: Use the proportion to find the amount of solute needed for 450 mL of solution.
(2 grams / 100 mL) = (x grams / 450 mL)
To solve for x, we can cross multiply:
100x = 2 * 450
100x = 900
x = 900 / 100
x = 9 grams
Therefore, you would need 9 grams of potassium chloride to prepare a 450 mL solution with a 2.0% (m/v) concentration.
To determine how much solute is needed to prepare a 2.0% (m/v) potassium chloride solution, you need to consider the definition of the concentration percentage. The given concentration, 2.0% (m/v), means that 2.0 grams of solute (potassium chloride) are present in every 100 milliliters of solution.
To find out the amount of solute needed to prepare a 450 ml solution, follow these steps:
Step 1: Determine the amount of solute in 100 ml solution.
Since the concentration is 2.0% (m/v), we know there are 2.0 grams of solute in 100 ml of solution.
Step 2: Calculate the amount of solute in 1 ml solution.
Divide the amount of solute in 100 ml by 100:
2.0 grams / 100 ml = 0.02 grams/ml
Step 3: Calculate the amount of solute needed for 450 ml solution.
Multiply the amount of solute in 1 ml by 450:
0.02 grams/ml × 450 ml = 9 grams
Therefore, to prepare a 450 ml solution of 2.0% (m/v) potassium chloride, you would need 9 grams of potassium chloride.