Solid aluminum carbonate decomposes to form solid aluminum oxide and carbon dioxide gas.
Is Al2(CO3)3 ==> Al2O3 + CO2 the right equation? If so, how do you balance this equation?
Al2(CO3)3==> Al2O3+3CO2
What about putting a 3CO2?
Well, it seems like you're trying to balance the equation Al2(CO3)3 → Al2O3 + CO2. Let me put on my balancing act!
First, let's take a look at the number of aluminum atoms. The left side has 2, while the right side only has 2. So far, so good!
Now, let's move on to the carbon atoms. The left side has 3 carbon atoms but the right side only has 1. Uh-oh, that's not quite balanced yet.
To fix this, we need to add a coefficient of 3 in front of CO2. Now we have:
Al2(CO3)3 → Al2O3 + 3CO2
Great, now all the carbon atoms are balanced! But wait, that means we have 6 oxygen atoms on the right side and only 3 on the left side.
To balance the oxygen atoms, we need to put a 3/2 coefficient in front of Al2O3. This gives us the final balanced equation:
Al2(CO3)3 → 3/2 Al2O3 + 3CO2
Voila! The equation is balanced and ready to put on a show.
Yes, the equation you provided is correct, but it is unbalanced.
To balance the equation, we need an equal number of atoms on both sides of the equation.
Let's start by balancing the aluminum (Al) atoms:
On the left-hand side, we have 2 Al atoms (Al2).
On the right-hand side, we have 2 Al atoms (Al2).
Now, let's balance the carbon (C) atoms:
On the left-hand side, we have 3 CO3 groups, which contain a total of 3 carbon atoms (3 x C).
On the right-hand side, we have 1 CO2 molecule, which contains 1 carbon atom (1 x C).
To balance the carbon atoms, we need to multiply the CO2 molecule by 3:
Al2(CO3)3 ⟶ Al2O3 + 3CO2
Finally, let's balance the oxygen (O) atoms:
On the left-hand side, we have 9 O atoms (3 x 3 from the CO3 groups).
On the right-hand side, we have 6 O atoms (2 from Al2O3 and 3 from 3CO2).
To balance the oxygen atoms, we need to multiply Al2O3 by 3:
Al2(CO3)3 ⟶ 3Al2O3 + 3CO2
Therefore, the balanced equation is:
2Al2(CO3)3 ⟶ 3Al2O3 + 3CO2
Yes, Al2(CO3)3 ==> Al2O3 + CO2 is the correct equation for the decomposition of solid aluminum carbonate.
To balance the equation, you need to ensure that the total number of atoms on both sides of the equation is the same.
Step 1: Count the atoms of each element on both sides of the equation.
On the left side (reactant side):
- Aluminum (Al): 2 atoms
- Carbon (C): 3 atoms (indicated by the subscript 3 in CO3)
- Oxygen (O): 9 atoms (3 atoms from CO3, and 6 atoms from the subscript 3 in Al2O3)
On the right side (product side):
- Aluminum (Al): 2 atoms (indicated by the subscript 2 in Al2O3)
- Carbon (C): 1 atom
- Oxygen (O): 3 atoms
Step 2: Balance the carbon (C) atoms:
There are three carbon atoms on the left side and only one on the right side. To balance the carbon atoms, you need to place a coefficient of 3 in front of the CO2:
Al2(CO3)3 ==> Al2O3 + 3CO2
Step 3: Balance the oxygen (O) atoms:
On the left side, there are 9 oxygen atoms (from CO3 and Al2O3). On the right side, there are only 3 oxygen atoms (from CO2). To balance the oxygen atoms, you need to place a coefficient of 3 in front of the Al2O3:
Al2(CO3)3 ==> 3Al2O3 + 3CO2
Step 4: Balance the aluminum (Al) atoms:
On both sides, there are already 4 aluminum atoms (2 from Al2(CO3)3 and 2 from 3Al2O3). Therefore, the equation is now balanced:
2 Al2(CO3)3 ==> 3 Al2O3 + 3 CO2