What is the fundamental frequency for tube resonating in water if the speed of sound was 343.5 and the tube was 0.274 m out of the water.
To find the fundamental frequency for a tube resonating in water, we need to use the formula:
f = (v / λ) / 2
Where:
f is the fundamental frequency (in Hz),
v is the speed of sound in the medium (in m/s),
and λ is the wavelength of the sound wave (in m).
In this case, the speed of sound in water is given as 343.5 m/s.
Now, to determine the wavelength of the sound wave, we need to take into account the length of the tube out of the water. Given that the tube is 0.274 m out of the water, the effective length (or open-closed length) will be half of that value since the tube is open at one end and closed at the other.
Thus, the effective length of the tube (λ) = 0.274 m / 2 = 0.137 m.
Now, we can substitute the values into the formula:
f = (343.5 m/s / 0.137 m) / 2
Simplifying the equation:
f = 1259.125 Hz
Therefore, the fundamental frequency for the tube resonating in water, given the provided information, is approximately 1259.125 Hz.