Write Skeleton equations for these reactions.

A) Heating Copper(II) sulfide in the Presence of diatomic oxygen produces pure copper and sulfur dioxide gas.

B)When heated, baking soda (Sodium hydrogen carbonate) decomposes to form the products sodium carbonate, carbon dioxide, and water.

CuS+O2

A) The skeleton equation for the reaction is:

CuS (s) + O2 (g) → Cu (s) + SO2 (g)

B) The skeleton equation for the reaction is:

2 NaHCO3 (s) → Na2CO3 (s) + CO2 (g) + H2O (g)

Sure! Let's break down the reactions and write the skeleton equations for each:

A) The reaction states that Copper(II) sulfide (CuS) is heated in the presence of diatomic oxygen (O2) to produce pure copper (Cu) and sulfur dioxide (SO2) gas.

The reactants in this reaction are:
Copper(II) sulfide (CuS) and diatomic oxygen (O2)

The products in this reaction are:
Pure copper (Cu) and sulfur dioxide gas (SO2)

The skeleton equation for this reaction would be:
CuS + O2 → Cu + SO2

B) The reaction states that baking soda, also known as sodium hydrogen carbonate (NaHCO3), is heated to produce the products sodium carbonate (Na2CO3), carbon dioxide gas (CO2), and water (H2O).

The reactant in this reaction is:
Baking soda or sodium hydrogen carbonate (NaHCO3)

The products in this reaction are:
Sodium carbonate (Na2CO3), carbon dioxide gas (CO2), and water (H2O)

The skeleton equation for this reaction would be:
NaHCO3 → Na2CO3 + CO2 + H2O

Remember that these are just skeleton equations, meaning they only provide a basic representation of the reactants and products involved. These equations can be balanced by adding coefficients to ensure that the number of atoms on both sides of the equation is equal.

These are done the same way as the next post. All are done the same way. Let me know if there is a particular something about any of these you don't understand.