Calculus
posted by LALA .
How do i find the derivative of
f(t)= 20 30/rooot 9 + t^2
heres how i did it
f'(x)= 20'  30/root(9+t^2) '
= 0  30/root(9+t^2) '
(Quotient rule)
f'(x)= 30' (root(9+t^2)  30(root(9+t^2) '
f'(x)= 30(0.5(9+t^2)^0.5) (2t)
the answer at the back of the book is 30t/(9+t^2)^1/2.... but i don't knohow to get it.
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