Calculate the mass of SO3 gas that forms when 10g of SO2 reacts with oxygen
1. Write the equation and balance it.
2. Convert what you have into moles. moles= grams/molar mass.
3. Using the coefficients in the balanced equation convert moles of what you have to moles of what you want.
4. Now convert moles of what you want to grams. g = moles x molar mass.
Post your work if you get stuck.
To solve this problem, we need to determine the balanced chemical equation for the reaction between SO2 and oxygen to form SO3. The balanced equation is as follows:
2SO2 + O2 → 2SO3
From the balanced equation, we can see that 2 moles of SO2 react with 1 mole of O2 to produce 2 moles of SO3.
Step 1: Convert the given mass of SO2 to moles.
To do this, we will use the molar mass of SO2, which is calculated by adding the atomic masses of sulfur (32.07 g/mol) and oxygen (2 × 16.00 g/mol). Therefore, the molar mass of SO2 is 64.07 g/mol.
Given mass of SO2 = 10 g
Molar mass of SO2 = 64.07 g/mol
Moles of SO2 = Given mass / Molar mass
= 10 g / 64.07 g/mol
≈ 0.1563 mol (rounded to four decimal places)
Step 2: Determine the moles of O2 required.
From the balanced chemical equation, we know that the molar ratio between SO2 and O2 is 2:1. Therefore, the moles of O2 required will be half the moles of SO2.
Moles of O2 = Moles of SO2 / 2
= 0.1563 mol / 2
= 0.07815 mol (rounded to five decimal places)
Step 3: Calculate the moles of SO3 produced.
From the balanced chemical equation, we know that 2 moles of SO2 produce 2 moles of SO3. Therefore, the moles of SO3 produced will be equal to the moles of O2.
Moles of SO3 = Moles of O2
= 0.07815 mol
Step 4: Convert the moles of SO3 to grams.
To convert moles to grams, we need to multiply the moles of SO3 by its molar mass. The molar mass of SO3 can be calculated by adding the atomic masses of sulfur (32.07 g/mol) and three oxygen atoms (3 × 16.00 g/mol). Therefore, the molar mass of SO3 is 80.06 g/mol.
Molar mass of SO3 = 80.06 g/mol
Mass of SO3 = Moles of SO3 × Molar mass of SO3
= 0.07815 mol × 80.06 g/mol
≈ 6.25 g (rounded to two decimal places)
Therefore, approximately 6.25 grams of SO3 gas will form when 10 grams of SO2 reacts with oxygen.