"if u could do this physics problem thatd be super.
A coach is hitting pop flies to the outfielders. If the baseball (m = 145 g) stays in contact with the bat for 0.04 s and leaves the bat with a speed of 50 m/s, what is the average force acting on the ball?"
Write down all the given then this problem might not be hard.
m of ball = 145 kg
t = 0.04 s
v = 50 m/s
Force(avg) = mass*acceleration(avg)
Also, acceleration(avg) = (delta)velocity/(delta)time, where delta represents change.
Now, solve for these variables:
acceleration(avg) = (50-0)/(.04-0) = 1250 m/s^2. Now calculate avg force:
Force(avg) = (.0145)(1250) = 18.125 N
To find the average force acting on the ball, we can use Newton's second law of motion, which states that the force acting on an object is equal to the change in momentum of the object divided by the time over which the change occurs.
1. First, we need to find the momentum of the ball before and after it is hit.
Momentum (p) is given by the equation: p = m * v, where m is the mass and v is the velocity.
The mass of the baseball is given as 145 g, which can be converted to kilograms by dividing by 1000. So, the mass (m) is 0.145 kg.
The velocity (v) after the ball is hit is given as 50 m/s.
Momentum before = m * v = 0.145 kg * 0 m/s = 0 kg⋅m/s
Momentum after = m * v = 0.145 kg * 50 m/s = 7.25 kg⋅m/s
2. Next, we find the change in momentum.
Change in momentum (Δp) = Momentum after - Momentum before = 7.25 kg⋅m/s - 0 kg⋅m/s = 7.25 kg⋅m/s
3. Now, we need to find the average force.
Average force (F) = Δp / t, where Δp is the change in momentum and t is the time over which the change occurs.
The time (t) is given as 0.04 s.
Average force = 7.25 kg⋅m/s / 0.04 s = 181.25 N
So, the average force acting on the ball is 181.25 Newtons.