Find two different perimeters of a rectangle with an area of 14 units. Nme their dimensions.
An area of 14 units is found by multiplying lxw which is probably 2x7; a rectangle has 2 long sides - 7
and 2 short sides - 2
The perimeter is the total of the sum of the sides.
2 + 2 + 7 + 7 = 18
It could also be 1 * 14 = area
1 + 1 + 14 + 14 = 30 for perimeter.
Do you have to limit yourself to whole numbers?
How about 4 * 3.5 = 14 = area
4 + 4 + 3.5 + 3.5 = 15
To find the two different perimeters of a rectangle with an area of 14 units, we need to determine the possible dimensions of the rectangle.
The area of a rectangle is given by the formula:
Area = length × width
In this case, the area is given as 14 units. Now, let's find the possible dimensions:
1. Start by determining the factors of 14. The factors of 14 are 1, 2, 7, and 14.
2. These factors represent the pairs of possible dimensions. So, we have two pairs: (1, 14) and (2, 7).
For the pair (1, 14):
- Length = 14 units
- Width = 1 unit
The perimeter of a rectangle is given by the formula:
Perimeter = 2 × (length + width)
Substituting the values, we get:
Perimeter = 2 × (14 + 1) = 30 units
For the pair (2, 7):
- Length = 7 units
- Width = 2 units
Again, substituting these values into the perimeter formula:
Perimeter = 2 × (7 + 2) = 18 units
Therefore, the two different perimeters of a rectangle with an area of 14 units are 30 units and 18 units. The dimensions for a perimeter of 30 units are length = 14 units and width = 1 unit, while the dimensions for a perimeter of 18 units are length = 7 units and width = 2 units.