If 4.32 g of solid C reacts stoichiometrically according to the balanced equation, how many grams of solid TiO2 are required?

3TiO2(s) + 4C(s) + 6Cl2(g) → 3TiCl4(l) + 2CO2(g) + 2CO(g)

4.32g C X (1/Molar Mass C)X (3 mol TiO2/ 4mol C) X (1 MOL/ Molar Mass TiO2)