Gaseous carbon monoxide reacts according to the balanced equation. If a total of 1040 kJ of heat is generated in the reaction as written, how many grams of CO2 are produced?
enthalpy=-566kJ
2 CO(g) + O2(g) → 2 CO2(g)
To determine the number of grams of CO2 produced, we can use the given amount of heat generated in the reaction and the enthalpy change of the reaction.
1. First, let's calculate the moles of CO(g) involved in the reaction. We have the balanced equation:
2 CO(g) + O2(g) → 2 CO2(g)
Since the stoichiometric ratio between CO and CO2 is 2:2, the amount of moles of CO is equal to the amount of moles of CO2 produced.
2. The enthalpy change of the reaction is -566 kJ. Since the reaction generates heat, the enthalpy change is negative.
3. Now, we can use the concept of molar enthalpy change to calculate the moles of CO involved in the reaction.
Enthalpy change (ΔH) is defined as the amount of heat involved in a reaction per mole of a substance. In this case, the enthalpy change (-566 kJ) refers to the reaction of 2 moles of CO.
4. Using a proportion, we can set up the following equation:
(-566 kJ) / (2 moles of CO) = (1040 kJ) / (x moles of CO)
where x is the number of moles of CO2 produced.
5. Solving the equation, we can find the value of x:
x = (1040 kJ * 2 moles of CO) / (-566 kJ)
x ≈ 7.335 moles
6. Finally, we can convert moles of CO2 to grams using the molar mass of CO2.
The molar mass of CO2 is approximately 44 g/mol.
7. Multiply the moles of CO2 by the molar mass:
mass of CO2 = 7.335 moles * 44 g/mol
mass of CO2 ≈ 322.74 g
Therefore, approximately 322.74 grams of CO2 are produced in the reaction.
To determine the number of grams of CO2 produced in the reaction, we need to use the given enthalpy change and the balanced equation.
First, let's convert the given enthalpy change from kJ to J:
1040 kJ = 1040 * 1000 J = 1,040,000 J
Next, we use the balanced equation to determine the mole ratio between CO and CO2. From the equation:
2 CO(g) + O2(g) → 2 CO2(g)
We see that 2 moles of CO are required to produce 2 moles of CO2. Therefore, the mole ratio is 1:1 between CO and CO2.
Now, we can use the enthalpy change to calculate the amount of CO2 produced. The enthalpy change is given per mole of CO, so we can set up the following equation using the equation's stoichiometry:
1,040,000 J = (-566 kJ) * n
n represents the number of moles of CO reacted. Rearranging the equation, we find:
n = - (1,040,000 J) / (566,000 J/mol)
n ≈ -1.837 moles
Since the mole ratio between CO and CO2 is 1:1, we can determine the number of moles of CO2 produced is also approximately -1.837 moles.
Finally, we can convert the number of moles of CO2 to grams using its molar mass. The molar mass of CO2 is approximately 44.01 g/mol. Therefore:
Mass of CO2 = number of moles * molar mass
Mass of CO2 = -1.837 mol * 44.01 g/mol
Mass of CO2 ≈ -80.55 g
Given that mass cannot be negative, we can conclude that approximately 80.55 grams of CO2 are produced in this reaction.