You have a bag with 60 black jelly beans and 240 red ones.

a) If you draw one jelly bean out of the bag, find the probability that it is black.
-------60/300= 1/5

b) If you add 60 black jelly beans to the original bag and draw out a bean, what is the probability that it is black?
-------120/360= 1/3

c) How many black beans do you need to add to the original bag to double the original probability of drawing a black bean?

d) Write an equation that represents the problem in part (c).

I GOT A AND B JUST NEED C AND D PLEASE?(:

Add x black beans.

Probability of drawing a black bean after adding more black beans
=(60+x)/(300+x)
If that has to be doubled from before (1/5=60/300), then
(60+x)/(300+x)=2*(1/5)
solve for x.

c) To double the original probability of drawing a black bean, we need to find the number of black beans that will make the probability 2/5.

Let's represent the number of black beans added as x.

The original probability of drawing a black bean is 1/5, and the new probability after adding x black beans is (60 + x)/(300 + x).

To double the original probability:
2/5 = (60 + x)/(300 + x)

d) The equation representing the problem in part (c) is:

2/5 = (60 + x)/(300 + x)

c) To double the original probability of drawing a black bean, we need to find the number of black beans that will make the probability equal to 2/5 (twice of 1/5).

Let the number of black beans to be added be represented by x.

The total number of beans in the bag after adding x black beans is 300 + x (as the original bag had 300 beans).

The probability of drawing a black bean after adding x black beans is (60 + x) / (300 + x).

Since we want this probability to be 2/5, we can set up the equation:

(60 + x) / (300 + x) = 2/5

d) The equation representing the problem in part (c) is:

(60 + x) / (300 + x) = 2/5