re:math
posted by larry .
i am having a minor difficulty
i've been stuck for over an hour and don't know what to do
i don't know is this right
? = "+" or ""
# = number
y=3
(x3)^2 + (y4)^2 = 9
i substitute y
(x3)^2 + (34)^2 = 9
(x3)^2 + 1 = 9
x^2  6x + 9 + 1 = 9
x^2  6x + 10 = 9
x^2  6x + 1 = 0
(x ? #)(x ? #) = 0
i get to here and now i am stuck
can u correct me if i did something wrong
please and thank you

re:math 
bobpursley
you are correct.
Use the quadratic formula
x= (b+sqrt (b^24ac))/2a
or do it this way:
(x3)^1+1=9
(x3)^2=8= 2*2^2
take the sqrt of each side
x3=+2*sqrt2
x= 3+sqrt2 or x=3sqrt2 
re:math 
larry
im confused

re:math 
bobpursley
Check with your teacher, then.
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