How mucyh heat is given up when 20 g of steam at 100 deg C is condensensed and cooled to 20 deg. C?
see above.
To calculate the amount of heat given up when steam is condensed and cooled, you need to use the equation:
q = m * C * ΔT
Where:
q = heat energy (in joules)
m = mass of the substance (in grams)
C = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
First, let's find the heat energy when steam is condensed to water:
The specific heat capacity of water is approximately 4.18 J/g°C.
Using the equation, q = m * C * ΔT, we can calculate the heat energy when steam is condensed:
q1 = m * C * (100 - 20)
Substituting the given values, we have:
q1 = 20g * 4.18 J/g°C * (100 - 20)
q1 = 20g * 4.18 J/g°C * 80
q1 = 6696 J
Therefore, when 20g of steam at 100°C is condensed to water, the amount of heat given up is 6696 J.
Next, let's find the heat energy when the water is cooled from 100°C to 20°C:
The specific heat capacity of water is still 4.18 J/g°C.
Using the equation, q = m * C * ΔT, we can calculate the heat energy when water is cooled:
q2 = m * C * (20 - 0)
Substituting the given values, we have:
q2 = 20g * 4.18 J/g°C * (20 - 0)
q2 = 20g * 4.18 J/g°C * 20
q2 = 1672 J
Therefore, when the water is further cooled from 100°C to 20°C, the amount of heat given up is 1672 J.
To find the total amount of heat given up when both processes occur, you can sum the two results:
Total heat given up = q1 + q2
Total heat given up = 6696 J + 1672 J = 8368 J
Therefore, the total amount of heat given up when 20g of steam at 100°C is condensed and cooled to 20°C is 8368 J.