calculus
posted by Anonymous .
suppose that the area under the curve y=1/x from x=a to x=b is k. the area in terms of k, under the curve y=1/x from x=2a to x=2b? justify

calculus 
bobpursley
INt x^1= lnx or k= ln(b/a)
so from 2a to 2b, areas is ln(2b/2a)= k
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