A 10 gram of mass of krypton occupies 15.0 L at a pressure of 210 kPa. What is the volume of the krypton when the pressure is increased to 790 kPa?
You can use P1V1 = P2V2
To find the volume of krypton when the pressure is increased to 790 kPa, we can use Boyle's Law. Boyle's Law states that the pressure and volume of a gas are inversely proportional, assuming temperature and amount of gas remain constant.
Boyle's Law can be expressed as:
P1 × V1 = P2 × V2
Where:
P1 = initial pressure (210 kPa)
V1 = initial volume (15.0 L)
P2 = final pressure (790 kPa)
V2 = final volume (unknown)
To solve for V2, we rearrange the equation:
V2 = (P1 × V1) / P2
Now let's substitute the given values into the equation:
V2 = (210 kPa × 15.0 L) / 790 kPa
V2 = 3150 kPa L / 790 kPa
V2 = 3.987 L
Therefore, the volume of krypton when the pressure is increased to 790 kPa is approximately 3.987 L.