If the following thiol containing compound is oxidized, what product will be obtained? CH3-SH -->
Can someone please help me with this? The only examples my book has are with two S, so I don't know how to do it with just one S. Thank you!!
It would appear from the attached site that the produce would be CH3-S-S-CH3
but look for confirmation.
http://www.cem.msu.edu/~reusch/VirtualText/special2.htm
To determine the product obtained from the oxidation of a thiol-containing compound, such as CH3-SH, you need to consider the oxidation state changes that occur in the chemical reaction.
In this case, the sulfur atom in the thiol (-SH) is typically oxidized to a sulfoxide (-SO) or a sulfonic acid (-SO3H). The specific product depends on the reaction conditions and the strength of the oxidizing agent used.
If a mild oxidizing agent is used, the thiol may be oxidized to a sulfoxide (R-SO-R'):
CH3-SH + [O] --> CH3-SO-CH3
In this reaction, the sulfur atom in CH3-SH undergoes oxidation, and an oxygen atom from the oxidizing agent replaces the sulfur atom. This forms a sulfoxide compound, CH3-SO-CH3.
On the other hand, if a stronger oxidizing agent is used, the thiol may be further oxidized to a sulfonic acid (R-SO3H):
CH3-SH + 2[O] --> CH3-SO3H
In this reaction, the sulfur atom in CH3-SH is fully oxidized to a sulfonic acid group, and two oxygen atoms from the oxidizing agent replace the sulfur atom. This forms a sulfonic acid compound, CH3-SO3H.
In summary, the specific product obtained from the oxidation of CH3-SH depends on the reagents and conditions used. It could result in either a sulfoxide (CH3-SO-CH3) or a sulfonic acid (CH3-SO3H) compound.