A baseball player with mass m = 80 kg, sliding into second base, is ed by a frictional force of magnitude 450 N. What is the coefficient of kinetic friction µk between the player and the ground?

450=mg*mu solve for mu

j k k k

To find the coefficient of kinetic friction (µk), we can use the formula:

Frictional force (F) = µk × Normal force (N)

In this case, we are given the mass of the baseball player (m = 80 kg) and the magnitude of the frictional force (F = 450 N).

To find the normal force, we can use Newton's second law, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

Net force (Fnet) = m × a

At this point, we can assume that the only force acting on the baseball player is the frictional force, which acts against the motion. So, the net force is equal to the frictional force:

Fnet = F = 450 N

Now, we need to calculate the acceleration (a) of the baseball player. We can use the equation:

Fnet = m × a

Substituting the known values, we have:

450 N = 80 kg × a

Solving for a, we get:

a = 450 N / 80 kg
a ≈ 5.625 m/s²

Now that we have the acceleration, we can find the normal force (N) using the equation:

Fnet = m × a = N - F

Substituting the known values, we have:

450 N = 80 kg × 5.625 m/s² + N

Solving for N, we get:

450 N - 450 N = 80 kg × 5.625 m/s²
N ≈ 0 N

Since the normal force is 0 N, it means that the player is not exerting any force perpendicular to the ground. This occurs when the player is sliding on the ground.

Finally, we can use the formula for frictional force (F) to find the coefficient of kinetic friction (µk):

F = µk × N

Substituting the known values, we have:

450 N = µk × 0 N

Since the normal force is 0 N, the frictional force is also 0 N. Therefore, the coefficient of kinetic friction (µk) in this situation is undefined.

In summary, in this scenario with the baseball player sliding into second base, the coefficient of kinetic friction cannot be determined because the normal force is zero.