How do i calculate the amount of heat required to raise the temperature of an 89 sample of water from 40 to 60.

q = mass water x specific heat water x delta T.

You have mass of water (no units---I suppose grams), Specific heat of water is 4.184 J/g*C and delta T is 60-40=20 IF those are degrees. You don't use units because you think they aren't important? Shame.

To calculate the amount of heat required to raise the temperature of a sample of water, you need to use the specific heat capacity of water and the formula for heat transfer:

Q = m * c * ΔT

Where:
- Q is the amount of heat transferred
- m is the mass of the substance (in this case, water)
- c is the specific heat capacity of water
- ΔT is the change in temperature

In this case, you want to calculate the amount of heat required to raise the temperature of 89g of water from 40°C to 60°C.

Step 1: Find the specific heat capacity of water.
The specific heat capacity of water is approximately 4.184 J/g°C.

Step 2: Calculate the change in temperature.
ΔT = Tfinal - Tinitial
ΔT = 60°C - 40°C
ΔT = 20°C

Step 3: Plug the values into the formula.
Q = m * c * ΔT
Q = 89g * 4.184 J/g°C * 20°C

Multiplying these values together will give you the amount of heat required to raise the temperature of the water sample from 40°C to 60°C.