If the 1 kg standard body has an acceleration of 2.00 m/s^2 at 20.0 degrees to the positive direction of an x axis
and....?
To understand how to get the answer to this question, we need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = m * a).
Given that the mass (m) of the standard body is 1 kg and the acceleration (a) is 2.00 m/s^2, we can calculate the force acting on the body.
To find the force in the x direction, we need to decompose the given angle into its x and y components. Since the angle is measured with respect to the positive x-axis, we can use trigonometry to determine these components.
The x-component can be found using the cosine function: cos(θ) = adjacent / hypotenuse. In this case, the adjacent side represents the x-component, and the hypotenuse is the total magnitude of the acceleration.
Given that the angle is 20.0 degrees and the total acceleration is 2.00 m/s^2, we can calculate the x-component as follows:
x-component = acceleration * cos(angle) = 2.00 m/s^2 * cos(20.0 degrees)
We can then substitute the known values to find the x-component of acceleration:
x-component = 2.00 m/s^2 * cos(20.0 degrees) = 2.00 m/s^2 * 0.9397 ≈ 1.88 m/s^2
Therefore, the x-component of the acceleration of the 1 kg standard body is approximately 1.88 m/s^2 in the positive direction of the x-axis.