A 155g sample of an unknown was heated from 25.0 to 40.00c absorbing 5696J of energy. what is the specific heat?

q = m*c*delta T

155g * 5696J * 15c (convert 15c to Joules)

To find the specific heat of the unknown substance, we can use the equation:

q = mcΔT

Where:
q = heat energy absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)

Given values:
q = 5696 J
m = 155 g
ΔT = 40.00°C - 25.0°C = 15.0°C

Now, we can rearrange the equation to solve for specific heat (c):

c = q / (m * ΔT)

Inserting the values we have:

c = 5696 J / (155 g * 15.0 °C)

Simplifying the expression:

c = 5696 J / 2325 g °C

Finally, dividing the numerator by the denominator:

c ≈ 2.45 J/g°C

Therefore, the specific heat of the unknown substance is approximately 2.45 J/g°C.