A 155g sample of an unknown was heated from 25.0 to 40.00c absorbing 5696J of energy. what is the specific heat?
q = m*c*delta T
155g * 5696J * 15c (convert 15c to Joules)
To find the specific heat of the unknown substance, we can use the equation:
q = mcΔT
Where:
q = heat energy absorbed (in Joules)
m = mass of the substance (in grams)
c = specific heat capacity (in J/g°C)
ΔT = change in temperature (in °C)
Given values:
q = 5696 J
m = 155 g
ΔT = 40.00°C - 25.0°C = 15.0°C
Now, we can rearrange the equation to solve for specific heat (c):
c = q / (m * ΔT)
Inserting the values we have:
c = 5696 J / (155 g * 15.0 °C)
Simplifying the expression:
c = 5696 J / 2325 g °C
Finally, dividing the numerator by the denominator:
c ≈ 2.45 J/g°C
Therefore, the specific heat of the unknown substance is approximately 2.45 J/g°C.