A football punter accelerates a football from rest to a speed of 8 m/s during the time in which his toe is in contact with the ball (about 0.16 s). If the football has a mass of 0.50 kg, what average force does the punter exert on the ball?
F=mass*changevelocity/timecontact
0.9
To find the average force exerted by the punter on the ball, we can use Newton's second law of motion, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). The formula is:
F = m * a
In this case, we know the mass of the football is 0.50 kg. However, we need to determine the acceleration.
Acceleration is defined as the change in velocity divided by the time taken. Given that the initial velocity (u) of the football is 0 m/s and the final velocity (v) is 8 m/s, we can use the following formula to find the acceleration (a):
a = (v - u) / t
where v is the final velocity, u is the initial velocity, and t is the time taken.
Substituting the values, we have:
a = (8 m/s - 0 m/s) / 0.16 s
a = 8 m/s / 0.16 s
a = 50 m/s^2
Now that we have the acceleration, we can calculate the average force exerted by the punter on the ball using the formula:
F = m * a
F = 0.50 kg * 50 m/s^2
F = 25 N
Therefore, the average force exerted by the punter on the ball is 25 Newtons.