You've made the finals of the Science Olympics! As one of your tasks, you're given 1.8g of copper and asked to make a wire, using all the metal, with a resistance of 1.3 Ohm. Copper has a density of 8900 kg/m^3.

What length will you choose for your wire(in meters)?

What diameter will you choose for your wire(in millimeters)?

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To determine the length and diameter of the wire required, we need to use the formula for the resistance of a wire:

Resistance (R) = (resistivity * length) / cross-sectional area

Given that the resistance is 1.3 Ohm and the copper wire has a resistivity of 1.68 x 10^(-8) Ohm·m, we can rearrange the formula to solve for length and cross-sectional area.

To find the length (L) of the wire:

1. Rearrange the formula to solve for length:

Length (L) = (Resistance * cross-sectional area) / resistivity

2. Calculate the cross-sectional area:

The mass (m) of the copper wire is given as 1.8g = 0.0018kg.
The density (ρ) of copper is 8900 kg/m^3.

The volume (V) of the wire can be calculated using the formula:

Volume (V) = mass / density

So, V = 0.0018kg / 8900 kg/m^3.

The cross-sectional area (A) can then be calculated using the formula:

Area (A) = V/L

Substituting the values we have:

A = (0.0018kg / 8900 kg/m^3) / L

3. Substitute the values into the length formula:

L = (Resistance * A) / resistivity

Substituting the resistance value of 1.3 Ohm, resistivity value of 1.68 x 10^(-8) Ohm·m, and the calculated value of A from step 2 will give us the length (L) of the wire.

To find the diameter (d) of the wire:

1. Use the formula for the cross-sectional area of a circle:

Area (A) = π * (d/2)^2

2. Rearrange the formula to solve for diameter:

d = √((4 * A) / π)

3. Substitute the calculated value of A from step 2 into the diameter formula.

Using these formulas, you can calculate the length and diameter of the wire.