lim (-x+10)/(x©÷-100)
x¡æ10
is this correct?
1/20
I do not understand your symbols.
lim (-x+10)/(x^2-100)
as x approaches 10
is 1/20 correct
-(x-10) /[(x-10)(x+10)]
= -1/(x+10)
---> -1/20
I get -1/20 as the limit.
To find the limit of the function (-x + 10)/(x^2 - 100) as x approaches 10, we can first factor the denominator:
x^2 - 100 = (x - 10)(x + 10)
Now, let's substitute x = 10 into the function:
(-10 + 10)/(10^2 - 100) = 0/0
We obtained an indeterminate form of 0/0, which means we need to further simplify the expression.
To do that, we can factor the numerator as well:
-x + 10 = -(x - 10)
Now our expression becomes:
-(x - 10)/((x - 10)(x + 10))
We can cancel out the common factor of (x - 10) in the numerator and the denominator:
-1/(x + 10)
Now let's substitute x = 10 into this simplified expression:
-1/(10 + 10) = -1/20
So, the correct limit is -1/20, not 1/20.