Show a complete algebraic solution for the following: find 4 consecutive multiples of 11 with the sum of 2178
n-1 + n + n+1 + n+2 = 2178
4 n + 2 = 2178
4 n = 2176
n = 544
n-1 = 543
so
543,544,etc
4 n + 2 = 2178
4 n = 2176
n = 544
n-1 = 543
so
543,544,etc