Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph, train B is traveling at 70 mph. Train A passes the station at 10:15pm. If train B passes the same station at 10:45pm at what time will train B catch train A?

__:__ (am/pm)
stuck on another one..word problems confuse me so bad..any help is greatly appreciated :)

Start measuring time from 10:45 AM. By that time, train A is 60 mph x 1/2 h = 30 miles ahead. The distance between the trains decreases at a rate 10 mph after that. The separation distance becomes zero after 30 miles/(10 miles/h) = 3 hours. B passes A at that time. Add three hours to 10:45 AM for the answer.

To solve this problem, you can use a formula: Distance = Speed x Time.

First, we need to determine the head start that Train A had. To do this, we find the distance that Train A traveled during the time it took Train B to pass the station. Since Train B passed the station 30 minutes (or 0.5 hours) after Train A, the head start for Train A can be calculated as follows:

Head start of Train A = Speed of Train A x Time taken by Train B = 60 mph x 0.5 hours = 30 miles

Now, we need to find out at what rate Train B is catching up to Train A. The relative speed between the two trains can be calculated as the difference in their speeds:

Relative speed = Speed of Train B - Speed of Train A = 70 mph - 60 mph = 10 mph

Finally, we can determine the time it takes for Train B to catch up to Train A by dividing the head start of Train A by the relative speed of the two trains:

Time taken = Head start / Relative speed = 30 miles / 10 mph = 3 hours

Since Train B passed the station at 10:45 pm, we can add the time taken (3 hours) to this to find the time Train B catches up to Train A:

10:45 pm + 3 hours = 1:45 am

Therefore, Train B will catch up to Train A at 1:45 am.